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x→∞lim ( x - 2/x + 3 )^2x = x→∞lim ( 1 - 5/x + 3 )^2x = e^-2b. Find b
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![Find : ("lim")(x->3^+)x/([x]) . Is it equal to : ("lim")(x->3^-)x/([x])](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/644361282_web.png "Find : (\"lim\")(x->3^+)x/([x]) . Is it equal to : (\"lim\")(x->3^-)x/([x])")
Find : ("lim")(x->3^+)x/([x]) . Is it equal to : ("lim")(x->3^-)x/([x])
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